Since reading this thread I've been giving the T2FD some serious consideration and research. Of particular interest is the function of the resistor at the "far end" of the antenna. Understanding its purpose should help in designing my own T2FD.
I found a very old post from this very forum describing (at least a portion) of the resistor's function which suggests why so many report the TF2D as having lower noise and better S/N than monoband dipoles:
The balancing resistor keeps the elements in perfect balance all the time in relation to the feedpoint, and THAT does a very effective job of canceling out local noise.
Having read elsewhere that "dummy loads have extremely flat SWR curves" and noting the T2FD is very wide-banded, the concern is how much energy is lost and how to minimize it. The same post from above includes this:
In addition, at MOST, the balancing resistor might cause a 3 dB drop in signal (1/2 an S-unit). Most of the time, it absorbs little, if any signal. Almost all signal is fed to the feedpoint through the folded dipoles because of the slightly lower resistance at the feedpoint that at the balance point. That is why for a 500 ohm feedpoint, you use a 540 to 600 ohm resistor in a terminated folded dipole.
As noted elsewhere in this thread, good performance from a T2FD depends heavily on the resistor value. The above post gives an explanation for why that is.
Is finding the feedpoint impedance simply a matter of deploying a T2FD, running the shortest possible 50-ohm coax to an analyzer and noting the R in an R,X scan?